Calcium oxide is the ce crystalline half of the white color. Name other words of speech - quick vape, calcium oxide, "kirabit", "kipilka". Calcium oxide, the formula of which is CaO, that yogo product of interaction with (H2O) water - Ca (OH) 2 (“fluff”, or quenching the vape) was widely known in everyday life.

How do you get calcium oxide?

1. The promissory way of cultivating this speech in a thermal (under temperature infusion) layout of a vapnyak:

CaCO3 (vapnyak) \u003d CaO (calcium oxide) + CO2 (carbon dioxide)

2. Calcium oxide can also be used for additional interaction of simple speeches:

2Ca (calcium) + O2 (kisen) \u003d 2CaO (calcium oxide)

3. The third way is to treat calcium in thermal decomposition of calcium hydroxide (Ca(OH)2) and calcium salts of cisnic acids:

2Ca(NO3)2 \u003d 2CaO (obtained speech) + 4NO2 + O2 (kysen)

calcium oxide

1. Zovnіshnіy vglyad: crystalline half of the white color. Crystallized after the type of sodium chloride (NaCl) in a cubic crystal face centering solution.

2. Molar mass becomes 55.07 g/mol.

3. Thickness is 3.3 g/cm.

Thermal power to calcium oxide

1. Melting temperature is 2570 degrees

2. Boiling temperature to become 2850 degrees

3. Molar heat capacity (for standard minds) is 42.06 J / (mol K)

4. Enthalpy of light (for standard minds) to become -635 kJ/mol

Chemical power of calcium oxide

Calcium oxide (formula CaO) is a basic oxide. Therefore, you can:

Disperse by the water (H2O) with the vision of energy. At which calcium hydroxide is dissolved. This reaction looks like this:

CaO (calcium oxide) + H2O (water) = Ca(OH)2 (calcium hydroxide) + 63.7 kJ/mol;

React with acids and acid oxides. Whose salts are established. Axis of applied reactions:

CaO (calcium oxide) + SO2 (sulfide anhydride) = CaSO3 (calcium sulfite)

CaO (calcium oxide) + 2HCl (hydrochloric acid) = CaCl2 (calcium chloride) + H2O (water).

Zastosuvannya calcium oxide:

1. The main obsyags of speech, which we are looking at, are vicarious during the production of a silicate chain in everyday life. In the past, quick-burning vape was victorious like vaping cement. Yogo was taken off when mixed with water (H2O). As a result, calcium oxide, turning into a hydroxide, which then turns into clay from the atmosphere (CO2), is very hard, transforming into calcium carbonate (CaCO3). Regardless of the cheapness of this method, in this hour of vaporization, cement practically does not stagnate in everyday life, so it’s good to collect wine and accumulate in your homeland.

2. As a fireproof material, calcium oxide is suitable as an inexpensive and accessible material. The melting of calcium oxide can be resistant to water (H2O), which allowed it to stagnate like a fire there, defiance of expensive materials is not sufficient.

3. Calcium is used in laboratories for drying quiet speeches, as they do not react with it.

4. At the kharchovіy galuzі speech is given as a kharchov additive under the designation E 529. Vykoristovuєtsya as an emulsifier for the creation of a homogeneous sumishi from speeches, so they do not mix with themselves - water, oil and fat.

5. In industry, calcium vicorous oxide is used for the removal of sulfuric anhydride (SO2) from flue gases. Zastosovuyut, as a rule, 15% of the water supply. As a result of the reaction, gypsum CaCO4 and CaCO3 appear in the interaction with sulfur dioxide. During the first hour of the experiment, the indicators were determined to be 98% of the purification of dimum in the form of sulfur dioxide.

6. Vykoristovuetsya in a special dish that "self-heating." A small amount of calcium oxide roztashovuetsya between two walls of the judge. When the capsules are pierced in the water, a reaction begins with the sight of a singing amount of heat.

Calcium oxide, the formula CaO, is often called quick-drying vape. A publication has been given to tell you about power, otrimannya, and also the stoppage of speech.

Appointment

Calcium oxide is a white crystalline speech. In some dzherelakh, yogo can be called calcium oxide, quick-drying vape, "boiling water" or kirabite. The quick-drying vapno is the most popular trivial name for the whole speech. The one and only calcium oxide.

power

Oxide is a crystalline speech that can be cubic mezhentrovaniya crystalline grati.

Wine melts at a temperature of 2570 °C, and boils at 2850 °C. Speech can be made salty. For this yoga, it is necessary to add acidic oxide to acidity.

Otrimannya

Yogo can be taken away for the help of thermal expansion of the vapnyak. The reaction proceeds as follows: calcium carbonate is heated step by step, and if the temperature of the medium reaches 900-1000 about C, the wine breaks down into gas-like carbon oxide and shukana rechovina. The second way of yoga obsession is the simplest reaction of the day. For which a small amount of pure calcium is omitted from rare kisen, if there is a reaction, the product of which will be the required oxide. Also, the rest can be removed in the process of deposition of calcium hydroxide or calcium salts of deacidic acidic acids at high temperatures. For example, let's look at the layout of the rest. If you take calcium nitrate (an excess of taking nitric acid) and heat it up to 500 about C, then the products of the reaction will be acid, nitrogen dioxide and calcium oxide, you know.

Zastosuvannya

In the main, the voice of vicory is galusi of everyday life, de s її additionally vibrate the silicate zegl. Previously, calcium oxide was zastosovuly and during the preparation of vape cement, and then later stopped exploitation through the selection of that accumulated cisco from the vologists. And if you want to vicorate for laying the stove, then when you roast it in the place, you will see asphyxiating carbon dioxide gas. Also, the speech is discussed at once with its own stamina to the point of water. Through this power, calcium oxide becomes a cheap and affordable fire extinguisher. Tsya half-heartedly necessary in any laboratories when draining speeches that do not react with it. Calcium oxide in one of the galuzes of the industry is used as a food additive E529. Also, 15% of the amount of speech is needed in order to remove the sulfur dioxide from certain gas-like fields. For additional calcium oxide, "self-heating" dishes are also vibrated. Tsya vlastіvіst zabezpechuєtsya process vіdіlennya heat pіd іn the reaction of calcium oxide with water.

Visnovok

Axis and all main information about the cost of the day. As it was guessed more, yoga is often called quick-drying vape. And chi know you, scho vapna in chemistry is more understandable? Use also extinguishing, chloride and sodium vapne.

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Chemical formula

Molar mass of CaO, calcium oxide 56.0774 g/mol

Massive parts of elements in each

Molar mass calculator wiki

• Chemical formulas must be entered from the improved register
• Indices are entered as an arithmetic number
• The point on the middle line (multiple sign), which zastosovuetsya, for example, in the formulas of crystal logic, is replaced by a significant point.
• Butt: instead of CuSO₄ 5H₂O at the converter for clarity of introduction, the spelling of CuSO4.5H2O is written.

Molar Mass Calculator

Mile

All speech is made up of atoms and molecules. In chemistry, it is important to accurately mimic the mass of speeches that enter into a reaction and become established as a result of it. For the purpose of the mole, the unity of the amount of speech SI. One mole avenges exactly 6.02214076 × 102 elementary particles. This value is numerically equal to Avogadro's constant N A , which is expressed in units of mole⁻¹ and is called Avogadro's number. Number of speeches (symbol n) systems of the world and the number of structural elements. A structural element can be an atom, a molecule, an ion, an electron, whether it be a part or a group of particles.

Constant Avogadro N A = 6.02214076×10² mol⁻¹. Avogadro's number is 6.02214076×10²³.

So a mole is the whole quantity of speech, which is more expensive for the sum of atomic masses of atoms and molecules of speech, multiplied by Avogadro's number. One of the seven basic units of the CI system is the mole. Shards of naming one and її mentally recognized zbіgayutsya, next to designate that mentally identifiable is not shilling for the name of one, as you can shilyat for the splendid rules of the Russian movie. One mole of pure carbon-12 is equal to exactly 12 g.

molar masa

The molar mass is the physical power of the speech, which stands as an extension of the mass of the speech to the amount of the speech in moles. Otherwise, it seems like a mass of one praying speech. System C1 has a molar mass unit of є kilogram/mol (kg/mol). However, the chemists sounded like a solid unit g/mol.

molar mass = g/mol

Molar mass of elements and spoluk

Half-shells are speeches that are made up of different atoms, like chemically tied together one by one. For example, pointing below the speech, as you can know in the kitchen of any gentleman, є chemistries:

• sil (sodium chloride) NaCl
• zukor (sucrose) C₁₂H₂₂O₁₁
• ocet (Octovoic Acid) CH₃COOH

The molar mass of chemical elements in grams per mole numerically changes with the mass of atoms of the element, as in atomic units of mass (or daltons). The molar mass is equal to the sum of the molar masses of the elements, including the sum of the sum of the days, with the adjustment of the number of atoms in the compound. For example, the molar mass of water (H₂O) is approximately equal to 1 × 2 + 16 = 18 g/mol.

molecular weight

Molecular mass (old name - molecular weight) - the mass of the molecule, is protected as the sum of the mass of the skin atom, which enters the warehouse of the molecule, multiplied by the number of atoms in this molecule. Molecular weight є worldless physical quantity, numerically equal to the molar mass. That is why the molecular weight changes in the form of a molar mass. Irrespective of those that have a molecular mass - an unfathomable value, it still has a value, called an atomic mass unit (a.m.u.) or a dalton (So), and approximately equal to the mass of one proton or a neutron. The atomic unit of mass is also numerically equal to 1 g/mol.

Rozrahunok molar mass

To loosen the molar mass like this:

• assign atomic masses of elements to the periodic table;
• determine the number of atoms of the skin element in the formula half;
• determine the molar mass, adding up the atomic mass of the elements that enter at the bottom, multiplied by their number.

For example, we dissolve the molar mass of optic acid

Won is accumulated from:

• two atoms in a coal
• a couple of atoms in water
• two atoms sour

• carbon C = 2 × 12.0107 g/mol = 24.0214 g/mol
• water H \u003d 4 × 1.00794 g / mol \u003d 4.03176 g / mol
• Kisen O = 2 × 15.9994 g/mol = 31.9988 g/mol
• molar mass = 24.0214 + 4.03176 + 31.9988 = 60.05196 g/mol

Our calculator beats such a mess. You can enter the formula of octic acid into the new one and revise it as you see.

Do you care about translating the same language in one language? Colleagues are ready to help you. Publish feed on TCTerms and with a stretch of kіlkoh whvilin you take away the evidence.

H 2 S + 2NaOH \u003d Na 2 S + 2H 2 O; (1)

H 2 S + NaOH = NaHS + H 2 O. (2)

Solution acids or foundation, what to take the fate of acid-base reactions, rozrakhovuetsya for the formula

M ek (acids, bases) = ,

de M is the molar mass of the acid and base; n- For acids- Number of atoms in water, substitutions in this reaction for metal; For pіdstav- The number of hydroxyl groups substituting in this reaction to acid excess.

The value of the equivalent of that molar mass of the equivalents of the speech is deposited in the reaction, in which the speech takes its fate.

In the reaction H 2 S + 2NaOH \u003d Na 2 S + 2H 2 O (1) two water molecules of H 2 S are replaced by metal i, in such a way, one water ion is equivalent to a ½ H 2 S.

E(H 2 S) = H 2 S, and M ek (H 2 S) = = 17 g / mol.

In the reaction H 2 S + NaOH \u003d NaHS + H 2 O (2) in the H 2 S molecule, only one ion of water is replaced by metal, and then, one ion is equivalent to the real part - the H 2 S molecule.

E(H 2 S) = H 2 S, and M ec (H 2 S) = = 34 g / mol.

The equivalent of NaOH in reactions (1) and (2) is equal to NaOH, since in both modes the acid excess is replaced by one hydroxyl group. Molar mass of NaOH equivalents

M eq (NaOH) = 40 g/mol.

Thus, the equivalent of H 2 S reaction (1) is equal to ½ H 2 S, reaction (2) −

1 H 2 S, molar mass equivalents of H 2 S equal to 17 (1) and 34 (2) g/mol; the equivalent of NaOH in reactions (1) and (2) is equal to NaOH, the molar mass of the base equivalent becomes 40 g/mol.

Solution. Molar mass equivalents oxide redeem for the formula

M ek (oxide) \u003d,

de M- molar mass of oxide; n- The number of cations in the hydroxide base or the number of anions in the hydroxide acid; |c.o.|- The absolute value of the oxidation state of the cation or anion.

The reaction P 2 O 5 + 3CaO \u003d Ca 3 (PO 4) 2 is equivalent to P 2 O 5 , which makes two triply charged anions (PO 4) 3-, 1/6 P 2 O 5 , and M ek (P 2 O 5) = = 23.7 g / mol. CaO equivalent, which gives one doubly charged cation (Ca 2+), more than ½ CaO, and M ec (CaO) = = 28 g/mol.

butt 2.3. Calculate the equivalent and molar mass equivalents of phosphorus in the columns PH 3 , P 2 Pro 3 and P 2 Pro 5 .

Solution. To calculate the molar mass of equivalents element at the same time, you can speed up with an offensive formula:

M ek (element) = ,

de M A- Molar mass of the element; |c.o.|- The absolute value of the oxidation state of the element.

Oxidation stage for phosphorus in PH 3, P 2 O 3 P 2 O 5 is generally good -3, +3 and +5. Submitting the value of the formula, it is known that the molar mass is equivalent to phosphorus in the PH 3 and P 2 Pro 3 half-folds 31/3 = 10.3 g / mol; in P 2 O 5 - 31/5 \u003d 6.2 g / mol, and the equivalent to phosphorus in the half of pH 3 and P 2 O 3 is more than 1/3 R, in the rear R 2 O 5 - 1/5 R.

Solution. Molar mass equivalents of chemical composition of the sum of molar masses of equivalents of warehouse parts:

M ek (PH 3) = M ek (P) + M ek(H) = 10.3 + 1 = 11 g/mol;

M ek (R 2 Pro 3) = M ek (P) + M ek(O) = 10.3 + 8 = 18.3 g/mol;

M ek (P 2 Pro 5) = M ek (P) + M ek (O) \u003d 6.2 + 8 \u003d 14.2 g / mol.

butt 2.5. For the introduction of 7.09 g of metal oxide with an oxidation level of +2, 2.24 liters of water are required for normal consumption. Calculate the molar mass equivalents of oxide and metal. Why is the molar mass of the metal valuable?

Solution. Zavdannya vyrіshuєtsya zgіdno іz the law of equivalents. So, as one of the reactive speeches is found in a gas-like camp, then it is easy to speed up with such a formula:

de V ek (gas) - obsyag one mole equivalent to gas. To calculate the number of moles of gas equivalents, it is necessary to know the number of moles of equivalents ( υ ) in one mole of gas: υ = . So, M(H 2) \u003d 2 g / mol; M ek (H 2) \u003d 1 g / mol. Later, in one mole of molecules, water H 2 is avenged υ \u003d 2/1 \u003d 2 mol equivalents of water. As you can see, moth be some kind of gas for normal minds (n.s.) ( T= 273 K, R\u003d 101.325 kPa) takes a volume of 22.4 liters. So, if a mole of water borrows a volume of 22.4 liters, shards in one mole of water are 2 moles equivalent to water, then one mole is equivalent to water V ek (H 2) \u003d 22.4 / 2 \u003d 11.2 l. Similarly M(Pro 2) \u003d 32 g / mol, M ek (O 2) \u003d 8 g / mol. In one mole of molecules, sour Pro 2 is avenged υ = 32/8 = 4 mol equivalents of sour. One mole equivalent to sour for normal minds borrow obsyag V ek (O 2) \u003d 22.4 / 4 \u003d 5.6 l.

Substituting the formula for numerical values, we know that M ek (oxide) = g/mol.

The molar mass is equivalent to the chemical composition of the sum of the molar masses of the equivalents of the warehouse parts. Oxide - z'ednannya metal with sour, to that molar mass is equivalent to oxide є sum M ek (oxide) = M ek (metal) + M ek (sour). Zvіdsi M ek (metal) = M ek (oxide) − M ek (sour) \u003d 35.45 - 8 \u003d 27.45 g / mol.

Molar mass of element equivalents ( M eq) is tied to the atomic mass of the element ( M A) spіvvіdnoshnyam: M ek(element) = , de ½ s.o.½ - element oxidation stage. Zvіdsi M A = M ek (metal) ∙ ½ s.o.½ = 27.45 x 2 = 54.9 g/mol.

in such a manner, M eq (oxide) = 35.45 g/mol; M eq (metal) = 27.45 g/mol; M A (metal) \u003d 54.9 g / mol.

butt 2.6. When interacting with nitrogen, 4 mol equivalents of nitric oxide (IV) were obtained. Razrahuvat obsyagi gazіv, yakі joined the reaction for normal minds.

Solution. Behind the law of equivalence is the number of moles of equivalent speeches that enter into a reaction and as a result of a reaction, equal to each other, tobto. υ (Pro 2) = υ (N 2) = υ (NO 2). Since 4 mol equivalents of nitrogen oxide (IV) were taken away, then, also, 4 mol equivalents of 2 and 4 mol equivalents of N 2 entered into the reaction.

Nitrogen changes the oxidation state from 0 (in N 2) to +4 (in NO 2), and since there are 2 atoms in the molecule, then 8 electrons are given away at the same time, so

M ek (N 2) \u003d \u003d 3.5 g / mol . Known volume, occupation by a mole equivalent to nitrogen (IV): 28 g / mol N 2 - 22.4 l

3.5 g/mol N 2 - X

X= l.

Oskіlki reaction entered 4 mol equivalents of N 2, they were able to become V(N 2) \u003d 2.8 4 \u003d 11.2 liters. Knowing that a mole equivalent to acid for normal minds takes a volume of 5.6 liters, a volume of 4 mole equivalents of O 2 is required, which reacted: V(O 2) \u003d 5.6 ∙ 4 \u003d 22.4 l.

Also, 11.2 liters of nitrogen and 22.4 liters of sour entered into the reaction.

butt 2.7. Calculate the molar mass equivalent to metal, so for 48.15 g of iodine oxide, 88.65 g of nitrate is taken.

Solution. Vrakhovuyuchi sho M ek (oxide) = M ek (metal) + M ek (sour), and M ek (salt) = M ek (metal) + M ek (acid excess), substantiating the relevant data to the law of equivalents:

stars M ek (metal) \u003d 56.2 g / mol.

butt 2.8. Calculate the degree of oxidation of chromium in oxide, which will cover 68.42% of that metal.

Solution. Taking the mass of oxide as 100%, we know the mass fraction of oxide in oxide: 100 - 68.42 = 31.58%, tobto. for 68.42 parts of masi chromium falls 31.58 parts of masi sour, or 68.42 g of chromium falls 31.58 g of sour. Knowing that the molar mass is equivalent to oxygen is 8 g/mol, it is significant that the molar mass is equivalent to chromium in oxide, according to the law of equivalents:

; M ek (Cr) = g/mol.

The degree of oxidation of chromium is known from spivv_dnosheniya,

stars | c. o.| = = 3.